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(C) The structure of tetrathionic acid $(H_2S_4O_6)$ is $HO-SO_2-S-S-SO_2-OH$. In this molecule,the two terminal sulphur atoms are in the $+5$ oxidati

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There are three $S-S$ linkages in a molecule

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(C) The structure of tetrathionic acid $(H_2S_4O_6)$ is $HO-SO_2-S-S-SO_2-OH$. In this molecule,the two terminal sulphur atoms are in the $+5$ oxidation state,while the two central sulphur atoms are in the $0$ oxidation state. Therefore,the oxidation states of all sulphur atoms are not the same. There are three $S-S$ linkages in the molecule ($S-S-S-S$ chain). The oxygen atoms are present in two environments: terminal $OH$ groups and double-bonded $O$ atoms,so their oxidation states are not all the same. The oxidation state of hydrogen is $+1$,not $-1$.

Compound	Oxidation number
$1$. $C_6H_{12}O_6$ (Carbon)	$a$. $+1$
$2$. $CCl_4$ (Carbon)	$b$. $0$
$3$. $NH_4Cl$ (Nitrogen)	$c$. $+4$
$4$. $Ba(H_2PO_2)_2$ (Phosphorus)	$d$. $-3$

Which of the following statements is correct regarding $H_2S_4O_6$?

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In which of the following, the oxidation state of nitrogen is lowest?

Match the following compounds with the oxidation number of the central atom (or specific atom in question):

Compound Oxidation number

$1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$

$2$. $CCl_4$ (Carbon) $b$. $0$

$3$. $NH_4Cl$ (Nitrogen) $c$. $+4$

$4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$

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